# Line slope calculator 5x-3y=30

**Straight line given by points A[6; 0] and B[9; 5]**

## Calculation:

**Slope-intercept form of line:**y = 1.6667x-10

**Canonical form of the line equation:**5x-3y-30 = 0

**Parametric form of the line equation:**

x = 3t+6

y = 5t ; t ∈ R

**Slope:**m = 1.6667

**Slope angle of line: φ =**59°2'10″ = 1.0304 rad

**X intercept:**x

_{0}= 6

**Y intercept:**y

_{0}= q = -10

**Distance line from the origin:**d

_{0}= 5.145

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(3; 5)

**Normal vector: n =**(5; -3)

**Midpoint of the segment AB: M =**[7.5; 2.5]

**Perpendicular Bisector equation:**3x+5y-35 = 0

**Vector OA = (6; 0) ; |OA| = 6**

**Vector OB = (9; 5) ; |OB| = 10.2956**

**Scalar product OA .OB = 54**

**Angle ∠ AOB = 29°3'17″ = 0.5071 rad**